Integrand size = 22, antiderivative size = 40 \[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4-d x^4}} \, dx=\frac {\operatorname {EllipticPi}\left (-\frac {2 b}{a \sqrt {d}},\arcsin \left (\frac {\sqrt [4]{d} x}{\sqrt {2}}\right ),-1\right )}{\sqrt {2} a \sqrt [4]{d}} \]
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Time = 0.01 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {1232} \[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4-d x^4}} \, dx=\frac {\operatorname {EllipticPi}\left (-\frac {2 b}{a \sqrt {d}},\arcsin \left (\frac {\sqrt [4]{d} x}{\sqrt {2}}\right ),-1\right )}{\sqrt {2} a \sqrt [4]{d}} \]
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Rule 1232
Rubi steps \begin{align*} \text {integral}& = \frac {\Pi \left (-\frac {2 b}{a \sqrt {d}};\left .\sin ^{-1}\left (\frac {\sqrt [4]{d} x}{\sqrt {2}}\right )\right |-1\right )}{\sqrt {2} a \sqrt [4]{d}} \\ \end{align*}
Result contains complex when optimal does not.
Time = 10.13 (sec) , antiderivative size = 59, normalized size of antiderivative = 1.48 \[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4-d x^4}} \, dx=-\frac {i \operatorname {EllipticPi}\left (-\frac {2 b}{a \sqrt {d}},i \text {arcsinh}\left (\frac {\sqrt {-\sqrt {d}} x}{\sqrt {2}}\right ),-1\right )}{\sqrt {2} a \sqrt {-\sqrt {d}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(77\) vs. \(2(32)=64\).
Time = 1.08 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.95
method | result | size |
default | \(\frac {\sqrt {2}\, \sqrt {1-\frac {x^{2} \sqrt {d}}{2}}\, \sqrt {1+\frac {x^{2} \sqrt {d}}{2}}\, \Pi \left (\frac {d^{\frac {1}{4}} x \sqrt {2}}{2}, -\frac {2 b}{a \sqrt {d}}, \frac {\sqrt {-\frac {\sqrt {d}}{2}}\, \sqrt {2}}{d^{\frac {1}{4}}}\right )}{a \,d^{\frac {1}{4}} \sqrt {-d \,x^{4}+4}}\) | \(78\) |
elliptic | \(\frac {\sqrt {2}\, \sqrt {1-\frac {x^{2} \sqrt {d}}{2}}\, \sqrt {1+\frac {x^{2} \sqrt {d}}{2}}\, \Pi \left (\frac {d^{\frac {1}{4}} x \sqrt {2}}{2}, -\frac {2 b}{a \sqrt {d}}, \frac {\sqrt {-\frac {\sqrt {d}}{2}}\, \sqrt {2}}{d^{\frac {1}{4}}}\right )}{a \,d^{\frac {1}{4}} \sqrt {-d \,x^{4}+4}}\) | \(78\) |
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\[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4-d x^4}} \, dx=\int { \frac {1}{\sqrt {-d x^{4} + 4} {\left (b x^{2} + a\right )}} \,d x } \]
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\[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4-d x^4}} \, dx=\int \frac {1}{\left (a + b x^{2}\right ) \sqrt {- d x^{4} + 4}}\, dx \]
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\[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4-d x^4}} \, dx=\int { \frac {1}{\sqrt {-d x^{4} + 4} {\left (b x^{2} + a\right )}} \,d x } \]
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\[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4-d x^4}} \, dx=\int { \frac {1}{\sqrt {-d x^{4} + 4} {\left (b x^{2} + a\right )}} \,d x } \]
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Timed out. \[ \int \frac {1}{\left (a+b x^2\right ) \sqrt {4-d x^4}} \, dx=\int \frac {1}{\left (b\,x^2+a\right )\,\sqrt {4-d\,x^4}} \,d x \]
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